According to IAU Circular No. 6202, the predicted magnitude of Comet Hale-Bopp will be -0.9 on 1997 March 3 and -1.4 on 1997 March 13. These magnitude estimates are based on the comet's current brightness, a pre-discovery photograph from 1993 April, and the assumption that the comet is not exhibiting any uncharacteristic outbursts. If these assumptions hold true, Hale-Bopp will shine at magnitude -1.2 during the total eclipse, making it an easy naked eye object. At that time, Hale Bopp will be north of Pegasus in Lacerta, some 46° from the Sun. For an observer on the center line north of Ulaanbaatar, the Sun will have an altitude of 12 ° and an azimuth of 112°. Comet Hale-Bopp will be conveniently located with an altitude of 55° and an azimuth of 89°.
The visibility of a comet during a total solar eclipse is quite a rare event and has only happened four times in the last century or so. Previous eclipse comets were observed in 1882, 1893, 1948 and 1963. Thus, the 1997 eclipse holds the promise of an especially unique and rare opportunity.
It should be emphasized that the above magnitude predictions for Comet Hale-Bopp are only educated 'guesstimates' based on the comet's current brightness and behavior. Due to the unpredictable nature of comet activity, it is impossible to accurately predict the brightness of a comet 18 months in advance. Nevertheless, Comet Hale-Bopp currently holds great promise in becoming the brightest comet seen in several decades.
Complete details for the Total Solar Eclipse of 1997 March 9 are available in NASA Reference Publication 1369.
Herewith my latest observations:
DATE [U.T.] mv Aper Type F/ DC COMA TAIL -------------------------------------------------- 1997 02 10.229 2.2 NE 8 1997 02 11.229 2.2 NE 8 1997 02 15.208 1.8 NE 8 10x50 B 5 8 3=B0 "U" shaped C90 C 11 1997 02 19.229 1.4 NE 8 10x50 B 5 8 C90 C 11 5=B0 "U"shaped, double with outburst 1997 02 20.236 1.4 NE 8 FM at 180=B0 1997 02 26.222 1.0 NE 8 10x50 B 5 8 C90 C 11 5=B0 "U" shaped, double tail with outburst. Moon behind clouds at approx. 150=B0I am leaving for Mo He Saturday March 1. All the best to everyone.
Best regards,
Patrick